Mathematics

Question

A pile of coins, consisting of quarters and half dollars, it worth $11.75. If there are 2 more quarters than half dollars, how many of each are there?

2 Answer

  • Let the number of half dollars be x,

    number of quarters = x + 2
    amount of half dollars = 0.5x
    amount of quarters = 0.25(x + 2)
    = 0.25x + 0.5
    total amount = 0.5x + 0.25x + 0.5
    = 0.75x + 0.5
    0.75x + 0.5 = 11.75
    0.75x = 11.25
    x = 15
    number of quarters = x + 2
    = 15 + 2
    = 17

    There are 17 quarters and 15 half dollars.
  • Let the number of half dollars be x,

    number of quarters = x + 2

    amount of half dollars = 0.5x

    amount of quarters = 0.25(x + 2)

    = 0.25x + 0.5

    total amount = 0.5x + 0.25x + 0.5

    = 0.75x + 0.5

    0.75x + 0.5 = 11.75

    0.75x = 11.25

    x = 15

    number of quarters = x + 2

    = 15 + 2

    = 17

    There are 17 quarters and 15 half dollars.