A rectangles length is 7 inches greater than its width. If the perimeter of the rectangle is 110 inches, find its length and width. I think it's w (w+7)=110
Mathematics
Anonym
Question
A rectangles length is 7 inches greater than its width. If the perimeter of the rectangle is 110 inches, find its length and width.
I think it's w (w+7)=110
I think it's w (w+7)=110
2 Answer

1. User Answers MiNk2019314
the equation for perimeter is P=2(l+w)
so, the equation is 110=2(l+w)
we know that l is 7 inches greater than w
so, l=w+7
now, substitute that for l
110=2(w+7+w)
110=2(2w+7)
110=4w+14
96=4w
w=24 
2. User Answers apologiabiology
ythat's wrong, perimiter is 2l+2w or 2(l+w) or just look below at my explanation
l=w+7
perimiter=2l+2w
perimiter=2(l+w)
subsitute
2(w+7+w)=permiter
2w+14+2w=4w+14=permiter
4w+14=110
subtract 14 from both sides
4w=96
divide both sides by 4
w=24
width=24
l=w+7
l=24+7
l=31
legnth=31
width=24