Mathematics

Question

A rectangles length is 7 inches greater than its width. If the perimeter of the rectangle is 110 inches, find its length and width.
I think it's w (w+7)=110

2 Answer

  • the equation for perimeter is P=2(l+w)
    so, the equation is 110=2(l+w)
    we know that l is 7 inches greater than w
    so, l=w+7
    now, substitute that for l
    110=2(w+7+w)
    110=2(2w+7)
    110=4w+14
    96=4w
    w=24
  • ythat's wrong, perimiter is 2l+2w or 2(l+w) or just look below at my explanation

    l=w+7

    perimiter=2l+2w
    perimiter=2(l+w)
    subsitute
    2(w+7+w)=permiter
    2w+14+2w=4w+14=permiter

    4w+14=110
    subtract 14 from both sides
    4w=96
    divide both sides by 4
    w=24

    width=24
    l=w+7
    l=24+7
    l=31


    legnth=31
    width=24