What is the sum of the positive integers k such that k/27 is greater than 2/3 and less than 8/9?

2 Answer

  • [tex]\dfrac{k}{27}>\dfrac{2}{3} \wedge \dfrac{k}{27}<\dfrac{8}{9}\\ k>18 \wedge k<24\\ k\in(18,24)\\\\ k\in(18,24) \wedge k\in \mathbb{Z}\\ k\in\{19,20,21,22,23\}\\\\ 19+20+21+22+23=\boxed{105} [/tex]
  • so we want to make them have the same denomenator so

    2/3 times 9/9=18/27
    8/9 times 3/3=24/27

    so k/27>18/27 and k/27<24/27 or

    the possible numbers for k are 19,20,21,22,23
    so the sum of the positive integers could be any positive whole numbers (1,2,3,4, etc) that add up to 19,20,21,22,23 exg 10,9      10,10     10,11  20,2  21,2 etc