h(x)= 1/8x^3x^2 What is the average rate of change of h over the interval −2≤x≤2?
Mathematics
Thoai
Question
h(x)= 1/8x^3x^2
What is the average rate of change of h over the interval −2≤x≤2?
What is the average rate of change of h over the interval −2≤x≤2?
1 Answer

1. User Answers jimrgrant1
Answer:
[tex]\frac{1}{2}[/tex]
Stepbystep explanation:
The average rate of change of h(x) in the closed interval [ a, b ] is
[tex]\frac{f(b)f(a)}{ba}[/tex]
Here [a, b ] = [  2, 2 ], thus
f(b) = f(2) = [tex]\frac{1}{8}[/tex] × 2³  2² = 1  4 =  3
f(a) = [tex]\frac{1}{8}[/tex] × ( 2)³  ( 2)² =  1  4 =  5
average rate of change = [tex]\frac{3(5)}{2(2)}[/tex] = [tex]\frac{2}{4}[/tex] = [tex]\frac{1}{2}[/tex]