F(x)= x^39x What is the average rate of change of f over the interval [1,6]?
Mathematics
SarahmC0922
Question
F(x)= x^39x
What is the average rate of change of f over the interval [1,6]?
What is the average rate of change of f over the interval [1,6]?
2 Answer

1. User Answers laurenh2021
Answer: 34
Stepbystep explanation:

2. User Answers sharmaaashutosh169
The average rate of change of f(x)= x³9x in interval [1,6] is 34.
Average rate of change
If f(x) is a function the [a,b] is interval then the average rate of change is [tex]\frac{f(b)f(a)}{ba}[/tex]
How to find the average rate of change of f?
Given the function is f(x)= x³9x and the interval is [1,6].
then first we have to find the value of f(1) and f(6).
So
f(1) = (1)³9(1)
= 19
= 8
and
f(6) = (6)³9(6)
= 216 54
= 162
therefore average rate of change of f is
[tex]\frac{f(6)f(1)}{61}= \frac{162+8}{61}[/tex]
= 170/5
= 34
Hence the average rate of change of f is 34.
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